Fractions-Solutions Ex-7.5

CBSE Class –VI Mathematics
NCERT Solutions
Chapter 7 Fraction (Ex. 7.5)

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Question 1. Write the fractions appropriately as additions or subtractions

Answer:  (a) 15+25=1+25=35$\frac{1}{5}+\frac{2}{5}=\frac{1+2}{5}=\frac{3}{5}$

(b) 55−35=5−35=25$\frac{5}{5}-\frac{3}{5}=\frac{5-3}{5}=\frac{2}{5}$

(c) 26+36=2+36=56$\frac{2}{6}+\frac{3}{6}=\frac{2+3}{6}=\frac{5}{6}$

Question 2. Solve:

(a) 118+118$\frac{1}{18}+\frac{1}{18}$

(b) 815+315$\frac{8}{15}+\frac{3}{15}$

(c) 77−57$\frac{7}{7}-\frac{5}{7}$

(d) 122+2122$\frac{1}{22}+\frac{21}{22}$

(e) 1215−715$\frac{12}{15}-\frac{7}{15}$

(f) 58+38$\frac{5}{8}+\frac{3}{8}$

(g) 1−23(1=33)$1-\frac{2}{3}\left(1=\frac{3}{3}\right)$

(h) 14+04$\frac{1}{4}+\frac{0}{4}$

(i) 3−125$3-\frac{12}{5}$

Answer: (a) 118+118=1+118=218=19$\frac{1}{18}+\frac{1}{18}=\frac{1+1}{18}=\frac{2}{18}=\frac{1}{9}$

(b) 815+315=8+315=1115$\frac{8}{15}+\frac{3}{15}=\frac{8+3}{15}=\frac{11}{15}$

(c) 77−57=7−57=27$\frac{7}{7}-\frac{5}{7}=\frac{7-5}{7}=\frac{2}{7}$

(d) 122+2122=1+2122=2222=1$\frac{1}{22}+\frac{21}{22}=\frac{1+21}{22}=\frac{22}{22}=1$

(e) 1215−715=12−715=515=13$\frac{12}{15}-\frac{7}{15}=\frac{12-7}{15}=\frac{5}{15}=\frac{1}{3}$

(f) 58+38=88=1$\frac{5}{8}+\frac{3}{8}=\frac{8}{8}=1$

(g) 1−23=33−23=3−22=13$1-\frac{2}{3}=\frac{3}{3}-\frac{2}{3}=\frac{3-2}{2}=\frac{1}{3}$

(h) 14+04=1+04=14$\frac{1}{4}+\frac{0}{4}=\frac{1+0}{4}=\frac{1}{4}$

(i) 3−125=155−125=15−125=35$3-\frac{12}{5}=\frac{15}{5}-\frac{12}{5}=\frac{15-12}{5}=\frac{3}{5}$

Question 3. Shubham painted 23$\frac{2}{3}$ of the wall space in his room. His sister Madhavi helped and painted 13$\frac{1}{3}$ of the wall space. How much did they paint together?

Answer: Fraction of the wall painted by Shubham = 23$\frac{2}{3}$

Fraction of the wall painted by Madhavi = 13$\frac{1}{3}$

Total painting done by both of them = 23+13=2+13=33=1$\frac{2}{3}+\frac{1}{3}=\frac{2+1}{3}=\frac{3}{3}=1$

Therefore, they painted the wall completely. 

Question 4. Fill in the missing fractions:

(a) 710− =310$\frac{7}{10}-\boxed{{\displaystyle }}=\frac{3}{10}$

(b)  −321=521$\boxed{{\displaystyle }}-\frac{3}{21}=\frac{5}{21}$

(c)  −36=36$\boxed{{\displaystyle }}-\frac{3}{6}=\frac{3}{6}$

(d)  +527=1227$\boxed{{\displaystyle }}+\frac{5}{27}=\frac{12}{27}$

Answer: (a) 410$\frac{4}{10}$

(b) 821$\frac{8}{21}$

(c) 66$\frac{6}{6}$

(d) 727$\frac{7}{27}$

Question 5.Javed was given a basket of  7 oranges, He sold only 5 oranges. What fraction of oranges was left in the basket?

Answer: Total = 1

Fraction of Orange left = 1−57$1-\frac{5}{7}$

= 77−57=7−57=27$\frac{7}{7}-\frac{5}{7}=\frac{7-5}{7}=\frac{2}{7}$

Thus, 27$\frac{2}{7}$ oranges was left in the basket.