Fractions-Solutions Ex-7.2

CBSE Class –VI Mathematics
NCERT Solutions
Chapter 7 Fraction (Ex. 7.2)

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Question 1. Draw number lines and locate the points on them:

(a)12,14,34,44$\frac{1}{2},\frac{1}{4},\frac{3}{4},\frac{4}{4}$

(b)18,28,38,78$\frac{1}{8},\frac{2}{8},\frac{3}{8},\frac{7}{8}$

(c)25,35,85,45$\frac{2}{5},\frac{3}{5},\frac{8}{5},\frac{4}{5}$

Answer:

Question 2. Express the following fractions as mixed fractions:

(a)203$\frac{20}{3}$   (b)115$\frac{11}{5}$  (c)177$\frac{17}{7}$  (d)285$\frac{28}{5}$   (e)196$\frac{19}{6}$   (f)359$\frac{35}{9}$

Answer: (a)

203=623$\frac{20}{3}=6\frac{2}{3}$

(b)

∴$\therefore$115=215$\frac{11}{5}=2\frac{1}{5}$

(c)

∴177=237$\therefore \frac{17}{7}=2\frac{3}{7}$

(d)

∴$\therefore$285=535$\frac{28}{5}=5\frac{3}{5}$

(e)

196=316$\frac{19}{6}=3\frac{1}{6}$

(f)

∴$\therefore$359=389$\frac{35}{9}=3\frac{8}{9}$

Question 3. Express the following as improper fractions:

(a)734$7\frac{3}{4}$  (b)567$5\frac{6}{7}$  (c)256$2\frac{5}{6}$  (d)1035$10\frac{3}{5}$  (e)937$9\frac{3}{7}$  (f)849$8\frac{4}{9}$

Answer: (a) 734=(7×4)+34=28+34=314$7\frac{3}{4}=\frac{\left(7\times 4\right)+3}{4}=\frac{28+3}{4}=\frac{31}{4}$

(b) 567=(5×7)+67=35+67=417$5\frac{6}{7}=\frac{\left(5\times 7\right)+6}{7}=\frac{35+6}{7}=\frac{41}{7}$

(c) 256=(2×6)+56=12+56=176$2\frac{5}{6}=\frac{\left(2\times 6\right)+5}{6}=\frac{12+5}{6}=\frac{17}{6}$

(d) 1035=(10×5)+35=50+35=535$10\frac{3}{5}=\frac{\left(10\times 5\right)+3}{5}=\frac{50+3}{5}=\frac{53}{5}$

(e) 937=(9×7)+37=63+37=667$9\frac{3}{7}=\frac{\left(9\times 7\right)+3}{7}=\frac{63+3}{7}=\frac{66}{7}$

(f) 849=(8×9)+49=72+49=769