### Fractions and Decimals - Solutions 7

CBSE Class –VII Mathematics
NCERT Solutions
Chapter 2 Fractions and Decimals
(Ex. 2.7)

Question 1. Find:
(i) 0.4 $÷$ 2
(ii) 0.35 $÷$ 5
(iii) 2.48 $÷$ 4
(iv) 65.4 $÷$ 6
(v) 651.2 $÷$ 4
(v) 14.49 $÷$ 7
(vii) 3.96 $÷$ 4
(viii) 0.80 $÷$ 5
Answer: (i) 0.4 $÷$ 2 = $\frac{4}{10}×\frac{1}{2}=\frac{2}{10}$ = 0.2
(ii) 0.35 $÷$ 5 = $\frac{35}{100}×\frac{1}{5}=\frac{7}{100}$ = 0.07
(iii)2.48 $÷$ 4 = $\frac{248}{100}×\frac{1}{4}=\frac{62}{100}$ = 0.62
(iv) 65.4 $÷$ 6 = $\frac{654}{10}×\frac{1}{6}=\frac{109}{10}$ = 10.9
(v) 651.2 $÷$ 4 = $\frac{6512}{10}×\frac{1}{4}=\frac{1628}{10}$ = 162.8
(vi)14.49 $÷$ 7 = $\frac{1449}{100}×\frac{1}{7}=\frac{207}{100}$ = 2.07
(vii)3.96 $÷$ 4 = $\frac{396}{100}×\frac{1}{4}=\frac{99}{100}$ = 0.99
(viii)0.80 $÷$ 5 = $\frac{80}{100}×\frac{1}{5}=\frac{16}{100}$ = 0.16
Question 2. Find:
(i) 4.8 $÷$ 10
(ii) 52.5 $÷$ 10
(iii) 0.7 $÷$ 10
(iv) 33.1 $÷$ 10
(v) 272.23 $÷$ 10
(vi) 0.56 $÷$ 10
(vii) 3.97 $÷$ 10
Answer: (i) 4.8 $÷$ 10 = $\frac{4.8}{10}$ = 0.48
(ii) 52.5 $÷$ 10 = $\frac{52.5}{10}$ = 5.25
(iii) 0.7 $÷$ 10 = $\frac{0.7}{10}$ = 0.07
(iv) 33.1 $÷$ 10 = $\frac{33.1}{10}$ = 3.31
(v) 272.23 $÷$ 10 = $\frac{272.23}{10}$ = 27.223
(vi) 0.56 $÷$ 10 = $\frac{0.56}{10}$ = 0.056
(vii) 3.97 $÷$ 10 = $\frac{3.97}{10}$ = 0.397
Question 3. Find:
(i) 2.7 $÷$ 100
(ii) 0.3 $÷$ 100
(iii) 0.78 $÷$ 100
(iv) 432.6 $÷$ 100
(v) 23.6 $÷$ 100
(vi) 98.53 $÷$ 100
Answer: (i) 2.7 $÷$ 100 = $\frac{27}{10}×\frac{1}{100}=\frac{27}{1000}$ = 0.027
(ii) 0.3 $÷$ 100 = $\frac{3}{10}×\frac{1}{100}=\frac{3}{1000}$ = 0.003
(iii) 0.78 $÷$ 100 = $\frac{78}{100}×\frac{1}{100}=\frac{78}{10000}$ = 0.0078
(iv) 432.6 $÷$ 100 = $\frac{4326}{10}×\frac{1}{100}=\frac{4326}{1000}$ = 4.326
(v) 23.6 $÷$ 100 = $\frac{236}{10}×\frac{1}{100}=\frac{236}{1000}$ = 0.236
(vi) 98.53 $÷$ 100 = $\frac{9853}{100}×\frac{1}{100}=\frac{9853}{10000}$ 0.9853
Question 4. Find:
(i) 7.9 $÷$ 1000
(ii) 26.3 $÷$ 1000
(iii) 38.53 $÷$ 1000
(iv) 128.9 $÷$ 1000
(v) 0.5 $÷$ 1000
Answer: (i) 7.9 $÷$ 1000 = $\frac{79}{10}×\frac{1}{1000}=\frac{79}{10000}$ = 0.0079
(ii) 26.3 $÷$ 1000 = $\frac{263}{10}×\frac{1}{1000}=\frac{263}{10000}$ = 0.0263
(iii) 38.53 $÷$ 1000 = $\frac{3853}{100}×\frac{1}{1000}=\frac{3853}{100000}$ = 0.03853
(iv) 128.9 $÷$ 1000 = $\frac{1289}{10}×\frac{1}{1000}=\frac{1289}{10000}$ = 0.1289
(v) 0.5 $÷$ 1000 = $\frac{5}{10}×\frac{1}{1000}=\frac{5}{10000}$ = 0.0005
Question 5. Find:
(i) 7 $÷$ 3.5
(ii) 36 $÷$ 0.2
(iii) 3.25 $÷$ 0.5
(iv) 30.94 $÷$ 0.7
(v) 0.5 $÷$ 0.25
(vi) 7.75 $÷$ 0.25
(vii) 76.5 $÷$ 0.15
(viii) 37.8 $÷$ 1.4
(ix) 2.73 $÷$ 1.3
Answer: (i) 7 $÷$ 3.5 = $7÷\frac{35}{10}=7×\frac{10}{35}=\frac{10}{5}$ = 2
(ii) 36 $÷$ 0.2 = $36÷\frac{2}{10}=36×\frac{10}{2}=$ 18 x 10 = 180
(iii) 3.25 $÷$ 0.5 = $\frac{325}{100}÷\frac{5}{10}=\frac{325}{100}×\frac{10}{5}=\frac{65}{10}$ = 6.5
(iv) 30.94 $÷$ 0.7 = $\frac{3094}{100}÷\frac{7}{10}=\frac{3094}{100}×\frac{10}{7}=\frac{442}{10}$ = 44.2
(v) 0.5 $÷$ 0.25 = $\frac{5}{10}÷\frac{25}{100}=\frac{5}{10}×\frac{100}{25}=\frac{10}{5}$ = 2
(vi) 7.75 $÷$ 0.25 = $\frac{775}{100}÷\frac{25}{100}=\frac{775}{100}×\frac{100}{25}$ = 31
(vii) 76.5 $÷$ 0.15 = $\frac{765}{10}÷\frac{15}{100}=\frac{765}{10}×\frac{100}{15}$ = 51 x 10 = 510
(viii) 37.8 $÷$ 1.4 = $\frac{378}{10}÷\frac{14}{10}=\frac{378}{10}×\frac{10}{14}$ = 27
(ix) 2.73 $÷$ 1.3 = $\frac{273}{100}÷\frac{13}{10}=\frac{273}{100}×\frac{10}{13}=\frac{21}{10}$ = 2.1
Question 6. A vehicle covers a distance of 43.2 km in 2.4 litres of petrol. How much distance will it cover in one litre petrol?
Answer$\because$ In 2.4 litres of petrol, distance covered by the vehicle = 43.2 km
$\therefore$ In 1 litre of petrol, distance covered by the vehicle = 43.2 $÷$ 2.4
$\frac{432}{10}÷\frac{24}{10}$ =